(1-3x)(x-2)+3(2-x)^2=0

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Solution for (1-3x)(x-2)+3(2-x)^2=0 equation: 



(1-3x)(x-2)+3(2-x)^2=0

We add all the numbers together, and all the variables

(-3x+1)(x-2)+3(-1x+2)^2=0

We multiply parentheses ..

(-3x^2+6x+x-2)+3(-1x+2)^2=0

We get rid of parentheses

-3x^2+6x+x+3(-1x+2)^2-2=0

We add all the numbers together, and all the variables

-3x^2+7x+3(-1x+2)^2-2=0

We move all terms containing x to the left, all other terms to the right

-3x^2+7x+3(-1x+2)^2=2

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